{"id":1179,"date":"2015-03-12T11:24:09","date_gmt":"2015-03-12T10:24:09","guid":{"rendered":"http:\/\/www.unimath.fr\/?p=1179"},"modified":"2019-05-04T08:51:06","modified_gmt":"2019-05-04T07:51:06","slug":"dm-guide-nombres-complexes-1","status":"publish","type":"post","link":"http:\/\/www.unimath.fr\/?p=1179","title":{"rendered":"DM guid\u00e9 Nombres complexes n\u00b01"},"content":{"rendered":"<p><strong>Sujet<\/strong> :\u00a0<a href=\"http:\/\/www.s431178539.onlinehome.fr\/wordpressnath\/wp-content\/uploads\/2015\/03\/E3-230215-DM-guide-complexes-conjugue.pdf\">Cliquer ici<\/a><br \/>\nCorrection en fin de cette page<\/p>\n<ol>\n<li>Calcul de l&rsquo;affixe de C&rsquo;<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion1&Prime;]R\u00e9ponse[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion1&Prime;] <img src='http:\/\/s0.wp.com\/latex.php?latex=%5Cfrac%7B-4%7D%7B5%7D%2B%5Cfrac%7B3%7D%7B5%7Di&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\frac{-4}{5}+\\frac{3}{5}i' title='\\frac{-4}{5}+\\frac{3}{5}i' class='latex' \/>[\/peekaboo_content]<br \/>\nMontrer que C&rsquo; appartient au cercle<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion2&Prime;]Aide[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion2&Prime;]Montrer que OC&rsquo; = 1 pour cela calculer le module de\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=z_%7BC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='z_{C}' title='z_{C}' class='latex' \/>&lsquo;[\/peekaboo_content]<br \/>\nMontrer que les points A, C et C&rsquo; sont align\u00e9s<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion3&Prime;]Aide 1[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion3&Prime;] On peut montrer que les vecteurs <img src='http:\/\/s0.wp.com\/latex.php?latex=%5Coverrightarrow%7BAC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\overrightarrow{AC}' title='\\overrightarrow{AC}' class='latex' \/> et\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=%5Coverrightarrow%7BAC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\overrightarrow{AC}' title='\\overrightarrow{AC}' class='latex' \/>&lsquo; sont colin\u00e9aires[\/peekaboo_content]<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion3b\u00a0\u00bb]Aide 2[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion3b\u00a0\u00bb]L&rsquo;affixe de\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=%5Coverrightarrow%7BAC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\overrightarrow{AC}' title='\\overrightarrow{AC}' class='latex' \/> est <img src='http:\/\/s0.wp.com\/latex.php?latex=-3%2Bi&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='-3+i' title='-3+i' class='latex' \/> et l&rsquo;affixe de\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=%5Coverrightarrow%7BAC%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\overrightarrow{AC}' title='\\overrightarrow{AC}' class='latex' \/>&lsquo; est\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=%5Cfrac%7B-9%7D%7B5%7D%2Bi%5Cfrac%7B3%7D%7B5%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\frac{-9}{5}+i\\frac{3}{5}' title='\\frac{-9}{5}+i\\frac{3}{5}' class='latex' \/>[\/peekaboo_content]<\/li>\n<li>Points ayant pour image A<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion4&Prime;]Aide 1[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion4&Prime;]Il faut r\u00e9soudre l&rsquo;\u00e9quation : z&rsquo; = <img src='http:\/\/s0.wp.com\/latex.php?latex=z_%7BA%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='z_{A}' title='z_{A}' class='latex' \/>[\/peekaboo_content]<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion4b\u00a0\u00bb]Aide 2[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion4b\u00a0\u00bb] Le probl\u00e8me revient \u00e0 r\u00e9soudre\u00a0une \u00e9quation en <img src='http:\/\/s0.wp.com\/latex.php?latex=z&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='z' title='z' class='latex' \/> et <img src='http:\/\/s0.wp.com\/latex.php?latex=%5Coverline%7Bz%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\overline{z}' title='\\overline{z}' class='latex' \/>, pour la r\u00e9soudre on peut poser <img src='http:\/\/s0.wp.com\/latex.php?latex=z%3Dx%2Biy&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='z=x+iy' title='z=x+iy' class='latex' \/> avec <img src='http:\/\/s0.wp.com\/latex.php?latex=x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x' title='x' class='latex' \/> \u00a0et <img src='http:\/\/s0.wp.com\/latex.php?latex=y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y' title='y' class='latex' \/> r\u00e9els.[\/peekaboo_content]<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion4c\u00a0\u00bb]R\u00e9ponse [\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion4c\u00a0\u00bb]M appartient \u00e0 <img src='http:\/\/s0.wp.com\/latex.php?latex=%5CDelta&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\Delta' title='\\Delta' class='latex' \/>\u00a0si et seulement si <img src='http:\/\/s0.wp.com\/latex.php?latex=x%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x=1' title='x=1' class='latex' \/>\u00a0et donc\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=%5CDelta&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\Delta' title='\\Delta' class='latex' \/> est la droite d&rsquo;\u00e9quation\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=x%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x=1' title='x=1' class='latex' \/>[\/peekaboo_content]<\/li>\n<li>Montrer que M&rsquo; appartient au cercle<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion5&Prime;]Aide 1[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion5&Prime;]Montrer que\u00a0OM&rsquo; = 1 en utilisant les propri\u00e9t\u00e9s des modules[\/peekaboo_content]<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion6&Prime;]Aide 2[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion6&Prime;] \u00a0On pourra utiliser : <img src='http:\/\/s0.wp.com\/latex.php?latex=%5Coverline%7Bz%7D-1%3D%5Coverline%7Bz-1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\overline{z}-1=\\overline{z-1}' title='\\overline{z}-1=\\overline{z-1}' class='latex' \/> d&rsquo;apr\u00e8s une propri\u00e9t\u00e9 des conjugu\u00e9s[\/peekaboo_content]<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion8&Prime;]Aide 3[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion8&Prime;] \u00a0On pourra utiliser que le module de\u00a0 <img src='http:\/\/s0.wp.com\/latex.php?latex=%5Coverline%7BZ%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\overline{Z}' title='\\overline{Z}' class='latex' \/> est \u00e9gal au module de <img src='http:\/\/s0.wp.com\/latex.php?latex=Z&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='Z' title='Z' class='latex' \/> pour tout complexe \u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=Z&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='Z' title='Z' class='latex' \/>[\/peekaboo_content]<\/li>\n<li>Montrer que la fraction est r\u00e9elle.<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion9&Prime;]Aide 1[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion9&Prime;]La fraction d\u00e9pend de\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=z&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='z' title='z' class='latex' \/> et <img src='http:\/\/s0.wp.com\/latex.php?latex=%5Coverline%7Bz%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\overline{z}' title='\\overline{z}' class='latex' \/>, on peut faire appara\u00eetre des r\u00e9els en posant\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=z%3Dx%2Biy&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='z=x+iy' title='z=x+iy' class='latex' \/> avec <img src='http:\/\/s0.wp.com\/latex.php?latex=x&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x' title='x' class='latex' \/> \u00a0et <img src='http:\/\/s0.wp.com\/latex.php?latex=y&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='y' title='y' class='latex' \/> r\u00e9els.[\/peekaboo_content]<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion10&Prime;]Aide 2[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion10&Prime;] La fraction est r\u00e9elle donc \u00e9gale \u00e0 un r\u00e9el k, ce qui nous am\u00e8ne \u00e0 conclure que des vecteurs sont colin\u00e9aires en reconnaissant des affixes de vecteurs dans la fraction [\/peekaboo_content]<\/li>\n<\/ol>\n<p><span style=\"color: #d62647;\"> Correction : <\/span>\u00a0<a href=\"http:\/\/www.s431178539.onlinehome.fr\/wordpressnath\/wp-content\/uploads\/2015\/03\/E3-230215-DM-guide-correction-complexes.pdf\" rel=\"\">cliquer ici<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Sujet :\u00a0Cliquer ici Correction en fin de cette page Calcul de l&rsquo;affixe de C&rsquo; [peekaboo_link name=\u00a0\u00bbquestion1&Prime;]R\u00e9ponse[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion1&Prime;] [\/peekaboo_content] Montrer que C&rsquo; appartient au cercle [peekaboo_link name=\u00a0\u00bbquestion2&Prime;]Aide[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion2&Prime;]Montrer que OC&rsquo; = 1 pour cela calculer le module de\u00a0&lsquo;[\/peekaboo_content] Montrer que les points A, C et C&rsquo; sont align\u00e9s [peekaboo_link name=\u00a0\u00bbquestion3&Prime;]Aide 1[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion3&Prime;] On peut montrer que [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[1],"tags":[],"_links":{"self":[{"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/posts\/1179"}],"collection":[{"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=1179"}],"version-history":[{"count":12,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/posts\/1179\/revisions"}],"predecessor-version":[{"id":3419,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/posts\/1179\/revisions\/3419"}],"wp:attachment":[{"href":"http:\/\/www.unimath.fr\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=1179"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=1179"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=1179"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}