{"id":1417,"date":"2015-04-12T10:28:11","date_gmt":"2015-04-12T09:28:11","guid":{"rendered":"http:\/\/www.unimath.fr\/?p=1417"},"modified":"2016-05-28T19:47:33","modified_gmt":"2016-05-28T18:47:33","slug":"dm-guide-nombres-complexes-3","status":"publish","type":"post","link":"http:\/\/www.unimath.fr\/?p=1417","title":{"rendered":"DM guid\u00e9 Nombres complexes 3"},"content":{"rendered":"<p><strong>Sujet :\u00a0<a href=\"http:\/\/www.s431178539.onlinehome.fr\/wordpressnath\/wp-content\/uploads\/2015\/04\/Suites-complexes-E2-190115-DM-guide.pdf\">Cliquer ici<\/a><\/strong><\/p>\n<ol>\n<li>Forme exponentielle<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion1&Prime;]R\u00e9ponse[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion1&Prime;]<img src='http:\/\/s0.wp.com\/latex.php?latex=%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D+e%5E%7Bi+%5Cfrac%7B%5Cpi%7D%7B6%7D%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\frac{\\sqrt{3}}{2} e^{i \\frac{\\pi}{6}}' title='\\frac{\\sqrt{3}}{2} e^{i \\frac{\\pi}{6}}' class='latex' \/>[\/peekaboo_content]<\/li>\n<li>a. Preuve suite\u00a0g\u00e9om\u00e9trique<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion3&Prime;]Aide[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion3&Prime;] <img src='http:\/\/s0.wp.com\/latex.php?latex=r_%7Bn%2B1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='r_{n+1}' title='r_{n+1}' class='latex' \/> est le module de <img src='http:\/\/s0.wp.com\/latex.php?latex=z_%7Bn%2B1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='z_{n+1}' title='z_{n+1}' class='latex' \/> puis utiliser la propri\u00e9t\u00e9 des modules qui consiste \u00e0 s\u00e9parer en deux modules quand il y a multiplication[\/peekaboo_content]<br \/>\nb. Expression en fonction de n<br \/>\n<span style=\"line-height: 1.714285714; font-size: 1rem;\">[peekaboo_link name=\u00a0\u00bbquestion3b\u00a0\u00bb]Aide [\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion3b\u00a0\u00bb]Formule classique du cours sur les suites g\u00e9om\u00e9triques [\/peekaboo_content]<br \/>\n<\/span><span style=\"font-size: 1rem; line-height: 1.714285714;\">[peekaboo_link name=\u00a0\u00bbquestion4&Prime;]R\u00e9ponse<\/span><span style=\"font-size: 1rem; line-height: 1.714285714;\">[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion4&Prime;]<img src='http:\/\/s0.wp.com\/latex.php?latex=r_n+%3D+%5Cleft%28%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%5Cright%29%5En&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='r_n = \\left(\\frac{\\sqrt{3}}{2}\\right)^n' title='r_n = \\left(\\frac{\\sqrt{3}}{2}\\right)^n' class='latex' \/> [\/peekaboo_content]<br \/>\nc. Distance <img src='http:\/\/s0.wp.com\/latex.php?latex=OA_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='OA_n' title='OA_n' class='latex' \/><br \/>\n<\/span><span style=\"line-height: 1.714285714; font-size: 1rem;\">[peekaboo_link name=\u00a0\u00bbquestion4b\u00a0\u00bb]Aide[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion4b\u00a0\u00bb]\u00a0<\/span><span style=\"line-height: 1.714285714; font-size: 1rem;\">\u00a0Traduire cette distance en terme de module[\/peekaboo_content]<br \/>\n<\/span>[peekaboo_link name=\u00a0\u00bbquestion4c\u00a0\u00bb]Aide 2 [\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion4c\u00a0\u00bb]Revoir le cours pour limite de <img src='http:\/\/s0.wp.com\/latex.php?latex=q%5En&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='q^n' title='q^n' class='latex' \/> [\/peekaboo_content]<br \/>\n<span style=\"line-height: 1.714285714; font-size: 1rem;\">[peekaboo_link name=\u00a0\u00bbquestion5&Prime;]R\u00e9ponse [\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion5&Prime;]La limite \u00e9tant \u00e9gale \u00e0 0, que peut-on en d\u00e9duire pour le point <img src='http:\/\/s0.wp.com\/latex.php?latex=A_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A_n' title='A_n' class='latex' \/> quand <img src='http:\/\/s0.wp.com\/latex.php?latex=n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n' title='n' class='latex' \/> tend vers <img src='http:\/\/s0.wp.com\/latex.php?latex=%2B%5Cinfty&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='+\\infty' title='+\\infty' class='latex' \/> ?[\/peekaboo_content]<\/span><\/li>\n<li><span style=\"line-height: 1.714285714; font-size: 1rem;\">Algorithme<br \/>\na. [peekaboo_link name=\u00a0\u00bbquestion10&Prime;]Valeur affich\u00e9e\u00a0[\/peekaboo_link]<br \/>\n[peekaboo_content name=\u00a0\u00bbquestion10&Prime;]n = 5[\/peekaboo_content]<br \/>\n<\/span>b. R\u00f4le de l&rsquo;algorithme ?<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion6&Prime;]R\u00e9ponse[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion6&Prime;]Il affiche le plus petit entier n tel que\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=r_n+%5Cleqslant+P&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='r_n \\leqslant P' title='r_n \\leqslant P' class='latex' \/><br \/>\n[\/peekaboo_content]<\/li>\n<li>a. Montrer que le triangle est rectangle<br \/>\n<span style=\"line-height: 1.714285714; font-size: 1rem;\">[peekaboo_link name=\u00a0\u00bbquestion12&Prime;]M\u00e9thode 1 [\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion12&Prime;]On peut montrer que l&rsquo;angle <img src='http:\/\/s0.wp.com\/latex.php?latex=%28%5Coverrightarrow%7BA_%7Bn%2B1%7DO%7D%2C+%5Coverrightarrow%7BA_%7Bn%2B1%7DA_%7Bn%7D%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(\\overrightarrow{A_{n+1}O}, \\overrightarrow{A_{n+1}A_{n}}' title='(\\overrightarrow{A_{n+1}O}, \\overrightarrow{A_{n+1}A_{n}}' class='latex' \/>) \u00a0est \u00e9gal \u00e0\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=%5Cfrac%7B%5Cpi%7D%7B2%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\frac{\\pi}{2} ' title='\\frac{\\pi}{2} ' class='latex' \/> ou\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=%5Cfrac%7B-%5Cpi%7D%7B2%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\frac{-\\pi}{2} ' title='\\frac{-\\pi}{2} ' class='latex' \/> en utilisant les arguments[\/peekaboo_content]<br \/>\n<\/span>[peekaboo_link name=\u00a0\u00bbquestion13&Prime;]M\u00e9thode 2[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion13&Prime;] On peut calculer les distances gr\u00e2ce aux modules et utiliser la r\u00e9ciproque du th\u00e9or\u00e8me de Pythagore\u00a0[\/peekaboo_content]<br \/>\nb.\u00a0Valeurs de n pour lesquelles <img src='http:\/\/s0.wp.com\/latex.php?latex=A_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A_n' title='A_n' class='latex' \/> est un point de l&rsquo;axe des ordonn\u00e9es<br \/>\n<span style=\"line-height: 1.714285714; font-size: 1rem;\">[peekaboo_link name=\u00a0\u00bbquestion15&Prime;]Aide[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion15&Prime;]Le point appartient \u00e0 l&rsquo;axe des ordonn\u00e9es si et seulement si <img src='http:\/\/s0.wp.com\/latex.php?latex=z_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='z_n' title='z_n' class='latex' \/> a pour argument <img src='http:\/\/s0.wp.com\/latex.php?latex=%5Cfrac%7B%5Cpi%7D%7B2%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\frac{\\pi}{2} ' title='\\frac{\\pi}{2} ' class='latex' \/> ou <img src='http:\/\/s0.wp.com\/latex.php?latex=%5Cfrac%7B-%5Cpi%7D%7B2%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\frac{-\\pi}{2} ' title='\\frac{-\\pi}{2} ' class='latex' \/> modulo <img src='http:\/\/s0.wp.com\/latex.php?latex=2%5Cpi&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='2\\pi' title='2\\pi' class='latex' \/> ce qui peut se traduire par argument \u00e9gal \u00e0\u00a0<img src='http:\/\/s0.wp.com\/latex.php?latex=%5Cfrac%7B%5Cpi%7D%7B2%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\frac{\\pi}{2} ' title='\\frac{\\pi}{2} ' class='latex' \/> modulo <img src='http:\/\/s0.wp.com\/latex.php?latex=%5Cpi&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\pi' title='\\pi' class='latex' \/> c&rsquo;est-\u00e0-dire <img src='http:\/\/s0.wp.com\/latex.php?latex=%5Cfrac%7B%5Cpi%7D%7B2%7D+%2B+k+%5Cpi&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\\frac{\\pi}{2} + k \\pi' title='\\frac{\\pi}{2} + k \\pi' class='latex' \/> avec <img src='http:\/\/s0.wp.com\/latex.php?latex=k+%5Cin+Z&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='k \\in Z' title='k \\in Z' class='latex' \/>[\/peekaboo_content]<br \/>\n<\/span>[peekaboo_link name=\u00a0\u00bbquestion16&Prime;]R\u00e9ponse[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion16&Prime;]n = 3 + 6k avec k entier naturel car n positif [\/peekaboo_content]<br \/>\nc. Construction.<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion17&Prime;]Aide 1[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion17&Prime;]Remarquer que <img src='http:\/\/s0.wp.com\/latex.php?latex=A_6&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='A_6' title='A_6' class='latex' \/> appartient \u00e0 l&rsquo;axe des abscisses et pour les autres points se rappeler que si ABC est rectangle en C alors C appartient au cercle de diam\u00e8tre [BC]. [\/peekaboo_content]<br \/>\n[peekaboo_link name=\u00a0\u00bbquestion18&Prime;]Aide 2[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion18&Prime;]Utiliser les angles d\u00e9j\u00e0 construits sur la figure et penser \u00e0 prolonger des droites[\/peekaboo_content]<\/li>\n<\/ol>\n<p>Correction : <a href=\"http:\/\/www.s431178539.onlinehome.fr\/wordpressnath\/wp-content\/uploads\/2016\/05\/Suites-complexes-E2-190115-DM-guide-correction.pdf\"rel=\"\">cliquer ici<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Sujet :\u00a0Cliquer ici Forme exponentielle [peekaboo_link name=\u00a0\u00bbquestion1&Prime;]R\u00e9ponse[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion1&Prime;][\/peekaboo_content] a. Preuve suite\u00a0g\u00e9om\u00e9trique [peekaboo_link name=\u00a0\u00bbquestion3&Prime;]Aide[\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion3&Prime;] est le module de puis utiliser la propri\u00e9t\u00e9 des modules qui consiste \u00e0 s\u00e9parer en deux modules quand il y a multiplication[\/peekaboo_content] b. Expression en fonction de n [peekaboo_link name=\u00a0\u00bbquestion3b\u00a0\u00bb]Aide [\/peekaboo_link][peekaboo_content name=\u00a0\u00bbquestion3b\u00a0\u00bb]Formule classique du cours sur les suites g\u00e9om\u00e9triques [\/peekaboo_content] [peekaboo_link [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[1],"tags":[],"_links":{"self":[{"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/posts\/1417"}],"collection":[{"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=1417"}],"version-history":[{"count":13,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/posts\/1417\/revisions"}],"predecessor-version":[{"id":2333,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=\/wp\/v2\/posts\/1417\/revisions\/2333"}],"wp:attachment":[{"href":"http:\/\/www.unimath.fr\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=1417"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=1417"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/www.unimath.fr\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=1417"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}